MHT CET · Chemistry · Electrochemistry
Which from following equations represents a correct relationship between standard cell potential and equilibrium constant for cell reaction?
- A \(\mathrm{E}_{\mathrm{cell}}^{\circ}=-\frac{2.303 \mathrm{RT}}{\mathrm{nF}}\)
- B \(\mathrm{E}_{\text {cell }}^{\circ}=\frac{0.0592}{\mathrm{nF}} \log _{10} \mathrm{~K}\)
- C \(\mathrm{E}_{\text {cell }}^{\circ}=\frac{0.0592}{\mathrm{n}} \log _{10} \mathrm{~K}\)
- D \(\mathrm{E}_{\text {cell }}^{\circ}=\frac{0.0592}{\mathrm{n}} \ln \mathrm{K}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{E}_{\text {cell }}^{\circ}=\frac{0.0592}{\mathrm{n}} \log _{10} \mathrm{~K}\)
Step-by-step Solution
Detailed explanation
The correct equation that represents the relationship between the standard cell potential and the equilibrium constant for the cell reaction is:
(3) \(E_{\text {cell }}^{\circ}=\frac{0.0592}{n} \log _{10}(K)\)
The general relationship between the standard cell potential \(E_{\text {cell }}^{\circ}\) and the equilibrium constant \(K\) is given by the Nernst equation, specifically in its standard form:
\(E_{\mathrm{cell}}^{\circ}=\frac{0.0592}{n} \log _{10}(K)\)
(3) \(E_{\text {cell }}^{\circ}=\frac{0.0592}{n} \log _{10}(K)\)
The general relationship between the standard cell potential \(E_{\text {cell }}^{\circ}\) and the equilibrium constant \(K\) is given by the Nernst equation, specifically in its standard form:
\(E_{\mathrm{cell}}^{\circ}=\frac{0.0592}{n} \log _{10}(K)\)
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