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MHT CET · Chemistry · Electrochemistry

Which from following equation is correct for relation between strandard cell potential and equilibrium constant?

  1. A \(\mathrm{E}_{\text {cell }}^0=\log _{10} \mathrm{~K} \frac{\mathrm{n}}{0.0592}\)
  2. B \(\mathrm{E}_{\text {cell }}^0=\frac{0.0592}{\mathrm{n}} \log _{10} \mathrm{~K}\)
  3. C \(\mathrm{E}_{\text {cell }}=\frac{0.0592}{\mathrm{n}} \log _{10} \mathrm{~K}\)
  4. D \(\mathrm{E}_{\text {cell }}=\log _{10} \mathrm{~K} \frac{\mathrm{n}}{0.0592}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\mathrm{E}_{\text {cell }}^0=\frac{0.0592}{\mathrm{n}} \log _{10} \mathrm{~K}\)

Step-by-step Solution

Detailed explanation

We know \(\mathrm{E}_{\text {cell }}=\mathrm{E}_{\text {cell }}^0-\frac{0.0592}{\mathrm{n}} \log _{10} \mathrm{Q}\)
Or at equilibrium \(0=\mathrm{E}_{\text {cell }}^0-\frac{0.0592}{\mathrm{n}} \log _{10} \mathrm{~K}\)
Or \(\mathrm{E}_{\text {cell }}^0=\frac{0.0592}{\mathrm{n}} \log _{10} \mathrm{~K}\)