MHT CET · Chemistry · Solid State
Which among the following crystal lattices occupies all of the cubic holes by cations?
- A \(\mathrm{SrCl}_{2}\)
- B \(\mathrm{CaF}_{2}\)
- C \(\mathrm{CsCl}\)
- D \(\mathrm{UO}_{2}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{CsCl}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{CsCl}\)
Cations inhabited all of the cubic holes in \(\mathrm{CsCl}\) crystal lattices. A single atom in the cube's centre belongs to this unit cell, and the unit cell has only one body centre. As a result, the compound's formula is \(\mathrm{CsCl}\), which stands for body-centred cubic cell. Particles are present in the corners of the cube, as well as one particle in the centre of the body, in this sort of cell.
Cations inhabited all of the cubic holes in \(\mathrm{CsCl}\) crystal lattices. A single atom in the cube's centre belongs to this unit cell, and the unit cell has only one body centre. As a result, the compound's formula is \(\mathrm{CsCl}\), which stands for body-centred cubic cell. Particles are present in the corners of the cube, as well as one particle in the centre of the body, in this sort of cell.
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