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MHT CET · Chemistry · Thermodynamics (C)

When \(6 \cdot 0 \mathrm{~g}\) of graphite reacts with dihydrogen to give methane gas, \(37 \cdot 4 \mathrm{~kJ}\) of heat is liberated. What is standard enthalpy of formation of \(\mathrm{CH}_{4_{(g)}}\) ?

  1. A \(112 \cdot 2 \mathrm{~kJ} \mathrm{~mol} \cdot 1\)
  2. B \(-74 \cdot 8 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
  3. C \(-37 \cdot 4 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
  4. D \(-112 \cdot 2 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-74 \cdot 8 \mathrm{~kJ} \mathrm{~mol}^{-1}\)

Step-by-step Solution

Detailed explanation

(A)
\(\mathrm{C}_{(8)}+2 \mathrm{H}_{2(8)} \longrightarrow \mathrm{CH}_{4(\mathrm{~g})}\)
For \(6.0 \mathrm{~g}\) of graphite, \(\Delta \mathrm{H}=-37.4 \mathrm{~kJ}\)
\(\therefore\) For \(12.0 \mathrm{~g}\) of graphite, \(\quad \Delta \mathrm{H}^{0}=\frac{-37.4 \times 12}{6}=-74.8 \mathrm{~kJ} \mathrm{~mol}^{-1}\)