MHT CET · Chemistry · Thermodynamics (C)
When \(6 \cdot 0 \mathrm{~g}\) of graphite reacts with dihydrogen to give methane gas, \(37 \cdot 4 \mathrm{~kJ}\) of heat is liberated. What is standard enthalpy of formation of \(\mathrm{CH}_{4_{(g)}}\) ?
- A \(112 \cdot 2 \mathrm{~kJ} \mathrm{~mol} \cdot 1\)
- B \(-74 \cdot 8 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- C \(-37 \cdot 4 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- D \(-112 \cdot 2 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(B) \(-74 \cdot 8 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
(A)
\(\mathrm{C}_{(8)}+2 \mathrm{H}_{2(8)} \longrightarrow \mathrm{CH}_{4(\mathrm{~g})}\)
For \(6.0 \mathrm{~g}\) of graphite, \(\Delta \mathrm{H}=-37.4 \mathrm{~kJ}\)
\(\therefore\) For \(12.0 \mathrm{~g}\) of graphite, \(\quad \Delta \mathrm{H}^{0}=\frac{-37.4 \times 12}{6}=-74.8 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
\(\mathrm{C}_{(8)}+2 \mathrm{H}_{2(8)} \longrightarrow \mathrm{CH}_{4(\mathrm{~g})}\)
For \(6.0 \mathrm{~g}\) of graphite, \(\Delta \mathrm{H}=-37.4 \mathrm{~kJ}\)
\(\therefore\) For \(12.0 \mathrm{~g}\) of graphite, \(\quad \Delta \mathrm{H}^{0}=\frac{-37.4 \times 12}{6}=-74.8 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
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