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MHT CET · Chemistry · Electrochemistry

What will be the concentration of solution of electrolyte if it's molar conductivity and conductivity are respectively \(230 \Omega^{-1}\) \(\mathrm{cm}^2 \mathrm{~mol}^{-1}\) and \(0.0115 \Omega^{-1} \mathrm{~cm}^{-1}\) at \(298 \mathrm{~K}\) ?

  1. A \(0.04 \mathrm{M}\)
  2. B \(0.03 \mathrm{M}\)
  3. C \(0.01 \mathrm{M}\)
  4. D \(0.05 \mathrm{M}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(0.05 \mathrm{M}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \Lambda_{\mathrm{m}}=\frac{\mathrm{k} \times 1000}{\mathrm{M}}\left(\begin{array}{c}\Lambda_{\mathrm{m}}=\text { Molar Conductivity } \\ \mathrm{k}=\text { Conductivity }\end{array}\right) \\ & 230=\frac{0.0115 \times 1000}{\mathrm{M}} \\ & \mathrm{M}=\frac{0.0115 \times 1000}{230}=0.05 \mathrm{M}\end{aligned}\)
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