MHT CET · Chemistry · Electrochemistry
What will be the concentration of NaCl solution, if the molar conductivity and conductivity of NaCl solution is \(124 \cdot 3 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}\) and \(1 \cdot 243 \times 10^{-4} \Omega^{-1} \mathrm{~cm}^{2}\)
respectively?
- A \(0.001\) mol \(\mathrm{L}^{-1}\)
- B \(0.01 \mathrm{~mol} \mathrm{~L}^{-1}\)
- C \(0.02\) mol \(I_{1}^{-1}\)
- D \(0.1 \mathrm{~mol} \mathrm{~L}^{-1}\)
Answer & Solution
Correct Answer
(A) \(0.001\) mol \(\mathrm{L}^{-1}\)
Step-by-step Solution
Detailed explanation
(D)
\(\Lambda=124.3 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}, \mathrm{k}=1.243 ~\times\) \(10^{-4} \Omega^{-1} \mathrm{~cm}^{2} \)
\( \mathrm{C}=? \)
\( \wedge=\frac{1000 \mathrm{k}}{\mathrm{C}} \quad \therefore \mathrm{C}=\frac{1000 \mathrm{k}}{\wedge} \)
\( \therefore \mathrm{C}=\frac{1000 \times 1.243 \times 10^{-4}}{124.3}=0.001 \mathrm{~mol} \mathrm{~L}^{-1}\)
\(\Lambda=124.3 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}, \mathrm{k}=1.243 ~\times\) \(10^{-4} \Omega^{-1} \mathrm{~cm}^{2} \)
\( \mathrm{C}=? \)
\( \wedge=\frac{1000 \mathrm{k}}{\mathrm{C}} \quad \therefore \mathrm{C}=\frac{1000 \mathrm{k}}{\wedge} \)
\( \therefore \mathrm{C}=\frac{1000 \times 1.243 \times 10^{-4}}{124.3}=0.001 \mathrm{~mol} \mathrm{~L}^{-1}\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- Identify the method used to obtain \(\mathrm{SO}_2\) gas in industry.MHT CET 2023 Easy
- What is IUPAC name of following compound?
MHT CET 2023 Medium - A conductivity cell containing \(5 \times 10^{-4} \mathrm{M} \mathrm{NaCl}\) solution develops resistance \(14000 \mathrm{ohms}\) at \(25^{\circ} \mathrm{C}\). Calculate the conductivity of solution if the cell constant is \(0.84 \mathrm{~cm}^{-1}\)MHT CET 2023 Easy
- What is the co-ordination number of a particle in fcc crystal lattice?MHT CET 2022 Easy
- Which from following compounds is NOT a mono carboxylic acid?MHT CET 2024 Medium
- Which from following compounds is used to prepare adipic acid using enzymes in green technology developed by Drath and Frost?MHT CET 2024 Hard
More PYQs from MHT CET
- Potassium metabisulphite is a(an)MHT CET 2010 Medium
- Given below are two statements.
Statement I: In root hair, outer layer of cell wall is composed of pectin.
Statement II: In root hair, inner layer of cell wall is composed of chitin.
Choose the correct answer from the options given below with reference to structure of root hair.MHT CET 2022 Hard - In the circuit given below, the current through inductor is \(0.9 \mathrm{~A}\) and through the capacitor is \(0.6 \mathrm{~A}\). The current drawn from the a.c. source is
MHT CET 2023 Medium - Identify the catalyst used in the manufacture of high density polythene.MHT CET 2020 Easy
- If \(\mathbf{a}+\mathbf{b}+\mathbf{c}=\mathbf{0}\) and \(|\mathbf{a}|=5,|\mathbf{b}|=3\) and \(|\mathbf{c}|=7\)
then angle between \(\mathbf{a}\) and \(\mathbf{b}\) isMHT CET 2012 Easy - A solution of non volatile solute is obtained by dissolving 2 g in 50 g benzene. Calculate the vapour pressure of solution if vapour pressure of pure benzene is 640 mmHg at \(25^{\circ} \mathrm{C}\).
[mol. mass of benzene \(=78 \mathrm{~g} \mathrm{~mol}^{-1}\), mol. mass of solute \(\left.=64 \mathrm{~g} \mathrm{~mol}^{-1}\right]\)MHT CET 2024 Hard