MHT CET · Chemistry · States of Matter
What volume of chlorine gas (molar mass 71) is evolved at STP during electrolysis of fused NaCl by passage of 1 amp current for 965 second? (At STP, V = \(22.4 . \mathrm{dm}^3\) )
- A 0.112 L
- B \(\quad 0.224 \mathrm{~L}\)
- C 1.12 L
- D \(\quad 2.24 \mathrm{~L}\)
Answer & Solution
Correct Answer
(A) 0.112 L
Step-by-step Solution
Detailed explanation
\(2 \mathrm{Cl}^{-} \longrightarrow \mathrm{Cl}_2+2 \mathrm{e}^{-}\)
For the reaction, mole ratio \(=\frac{1}{2}\)
Moles of product formed
\(\begin{aligned}
& =\frac{\mathrm{I}(\mathrm{~A}) \times \mathrm{t}(\mathrm{~s})}{96500\left(\mathrm{C} \mathrm{~mol}^{-1}\right)} \times \text { mole ratio } \\
& =\frac{1 \times 965}{96500} \times \frac{1}{2} \\
& =5 \times 10^{-3} \mathrm{~mol}
\end{aligned}\)
\(\begin{aligned}
& \text { At STP, } 1 \mathrm{~mol} \mathrm{Cl}_{2(\mathrm{~g})}=22.4 \mathrm{dm}^3 \\
\therefore \quad & \text { At STP, } 5 \times 10^{-3} \mathrm{~mol} \mathrm{Cl}_{2(\mathrm{~g})}=0.112 \mathrm{~L}
\end{aligned}\)
For the reaction, mole ratio \(=\frac{1}{2}\)
Moles of product formed
\(\begin{aligned}
& =\frac{\mathrm{I}(\mathrm{~A}) \times \mathrm{t}(\mathrm{~s})}{96500\left(\mathrm{C} \mathrm{~mol}^{-1}\right)} \times \text { mole ratio } \\
& =\frac{1 \times 965}{96500} \times \frac{1}{2} \\
& =5 \times 10^{-3} \mathrm{~mol}
\end{aligned}\)
\(\begin{aligned}
& \text { At STP, } 1 \mathrm{~mol} \mathrm{Cl}_{2(\mathrm{~g})}=22.4 \mathrm{dm}^3 \\
\therefore \quad & \text { At STP, } 5 \times 10^{-3} \mathrm{~mol} \mathrm{Cl}_{2(\mathrm{~g})}=0.112 \mathrm{~L}
\end{aligned}\)
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