MHT CET · Chemistry · Some Basic Concepts of Chemistry
What volume of \(2 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}\) is required to form \(0.2 \mathrm{~N}\) of \(100 \mathrm{~mL}\) of solution?
- A \(5 \mathrm{~mL}\)
- B \(20 \mathrm{~mL}\)
- C \(10 \mathrm{~mL}\)
- D \(50 \mathrm{~mL}\)
Answer & Solution
Correct Answer
(A) \(5 \mathrm{~mL}\)
Step-by-step Solution
Detailed explanation
\(\because \mathrm{M}-\mathrm{H}_{2} \mathrm{SO}_{4}=2 \mathrm{~N}-\mathrm{H}_{2} \mathrm{SO}_{4}\)
\(\therefore 2 \mathrm{M}-\mathrm{H}_{2} \mathrm{SO}_{4}=4 \mathrm{~N}-\mathrm{H}_{2} \mathrm{SO}_{4}\)
\(N_{1} V_{1}=N_{2} V_{2}\)
\(4 \times V_{1}=0.2 \times 100\)
\(V_{1}=\frac{0.2 \times 100}{4}\)
\(=5 \mathrm{~mL}\)
\(\therefore 2 \mathrm{M}-\mathrm{H}_{2} \mathrm{SO}_{4}=4 \mathrm{~N}-\mathrm{H}_{2} \mathrm{SO}_{4}\)
\(N_{1} V_{1}=N_{2} V_{2}\)
\(4 \times V_{1}=0.2 \times 100\)
\(V_{1}=\frac{0.2 \times 100}{4}\)
\(=5 \mathrm{~mL}\)
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