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MHT CET · Chemistry · Thermodynamics (C)

What is the work done when a gas is compressed from \(2.5 \times\) \(10^{-2} \mathrm{~m}^3\) to \(1.3 \times 10^{-2} \mathrm{~m}^3\) at constant external pressure of 4.05 bar?

  1. A \(4050 \mathrm{~J}\)
  2. B \(4400 \mathrm{~J}\)
  3. C \(4200 \mathrm{~J}\)
  4. D \(4860 \mathrm{~J}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(4860 \mathrm{~J}\)

Step-by-step Solution

Detailed explanation

\(
\begin{aligned}
& \mathrm{W}=-\operatorname{Pext}\left[\mathrm{V}_2-\mathrm{V}_1\right] \\
& =-4.05\left[1.3 \times 10^{-2}-2.5 \times 10^{-2}\right] \\
& =4.05 \times 1.2 \times 10^{-2}=4.86 \times 10^{-2} \mathrm{bar}-\mathrm{m}^3 \\
& \left(1 \mathrm{bar}=10^5 \mathrm{~Pa}, 1 \mathrm{~Pa}-\mathrm{m}^3=1 \mathrm{~J}\right) \\
& \mathrm{W}=4.86 \times 10^{-2} \times 10^5 \mathrm{~Pa}-\mathrm{m}^2 \\
& =4860 \mathrm{~J}
\end{aligned}
\)