MHT CET · Chemistry · Structure of Atom
What is the wave number of photon emitted during transition from orbit, \(\mathrm{n}=4\) to \(\mathrm{n}=2\) in hydrogen atom \(\left[\mathrm{R}_{\mathrm{H}}=109677 \mathrm{~cm}^{-1}\right]\)
- A \(20564.44 \mathrm{~cm}^{-1}\)
- B \(23032.17 \mathrm{~cm}^{-1}\)
- C \(15354.78 \mathrm{~cm}^{-1}\)
- D \(25225.7 \mathrm{~cm}^{-1}\)
Answer & Solution
Correct Answer
(A) \(20564.44 \mathrm{~cm}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \bar{v} & =109677\left[\frac{1}{2^2}-\frac{1}{4^2}\right] \mathrm{cm}^{-1} \\ & =109677\left[\frac{1}{4}-\frac{1}{16}\right] \mathrm{cm}^{-1} \\ & =109677\left[\frac{12}{64}\right] \mathrm{cm}^{-1} \\ & =20564.44 \mathrm{~cm}^{-1}\end{aligned}\)
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