MHT CET · Chemistry · Some Basic Concepts of Chemistry
What is the volume of oxygen required for complete combustion of 0.25 mole of methane at S.T.P.?
- A \(22.4 \mathrm{dm}^3\)
- B \(5.6 \mathrm{dm}^3\)
- C \(11.2 \mathrm{dm}^3\)
- D \(7.46 \mathrm{dm}^3\)
Answer & Solution
Correct Answer
(C) \(11.2 \mathrm{dm}^3\)
Step-by-step Solution
Detailed explanation
\(\mathrm{CH}_4+2 \mathrm{O}_2 \longrightarrow \mathrm{CO}_2+2 \mathrm{H}_2 \mathrm{O} \)
\( 1 \text { mole of } \mathrm{CH}_4 \text { requires }=2 \times 22.4 \mathrm{dm}^3 \text { of } \mathrm{O}_2 \)
\( \therefore 0.25 \text { mole of methane requires } \)
\( = 2 \times 22.4 \times 0.25=11.2 \mathrm{dm}^3 \text { of } \mathrm{O}_2\)
\( 1 \text { mole of } \mathrm{CH}_4 \text { requires }=2 \times 22.4 \mathrm{dm}^3 \text { of } \mathrm{O}_2 \)
\( \therefore 0.25 \text { mole of methane requires } \)
\( = 2 \times 22.4 \times 0.25=11.2 \mathrm{dm}^3 \text { of } \mathrm{O}_2\)
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