MHT CET · Chemistry · Solid State
What is the volume of 1 mole of a crystalline solid having unit cell edge length \(16 \times 10^{-8} \mathrm{~cm}\), if it's unit cell contains 24 molecules?
- A \(102 \cdot 7 \mathrm{~cm}^{3} \mathrm{~mol}^{-1}\)
- B \(404 \cdot 0 \mathrm{~cm}^{3} \mathrm{~mol}^{-1}\)
- C \(159 \cdot 3 \mathrm{~cm}^{3} \mathrm{~mol}^{-1}\)
- D \(142 \cdot 1 \mathrm{~cm}^{3} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(A) \(102 \cdot 7 \mathrm{~cm}^{3} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\(16 \times 10^{-8} \mathrm{~cm}\)
\(a=16 \times 10^{-8}\) cme unit cell \(=a^{3}=\left(16 \times 10^{-8}\right)^{3}\)
Volume of one unit cellat \(=4096 \times 10^{-24} \mathrm{~cm}^{3}\)
volume of 24 molecules \(=4096 \times 10^{-24} \mathrm{~cm}^{3}\)
\(\therefore\) Volume of 1 molecule \(=\frac{4096 \times 10^{-24}}{24}=170.67 \times 10^{-24} \mathrm{~cm}^{3}\)
\(\therefore\) Volume of 1 mole of a crystalline solid \(=170.67 \times 10^{-24} \times 6.022 \times 10^{23}\)
\(=1027.77 \times 10^{-1}\)
\(a=16 \times 10^{-8}\) cme unit cell \(=a^{3}=\left(16 \times 10^{-8}\right)^{3}\)
Volume of one unit cellat \(=4096 \times 10^{-24} \mathrm{~cm}^{3}\)
volume of 24 molecules \(=4096 \times 10^{-24} \mathrm{~cm}^{3}\)
\(\therefore\) Volume of 1 molecule \(=\frac{4096 \times 10^{-24}}{24}=170.67 \times 10^{-24} \mathrm{~cm}^{3}\)
\(\therefore\) Volume of 1 mole of a crystalline solid \(=170.67 \times 10^{-24} \times 6.022 \times 10^{23}\)
\(=1027.77 \times 10^{-1}\)
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