MHT CET · Chemistry · Surface Chemistry
What is the value of slope in Freundlich adsorption isotherm \(\log \frac{\mathrm{x}}{\mathrm{m}}\) against \(\log \mathrm{C}\) ?
- A \(\frac{1}{\mathrm{n}}\)
- B n
- C K
- D \(\quad \log \mathrm{K}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{\mathrm{n}}\)
Step-by-step Solution
Detailed explanation
According to Freundlich's adsorption isotherm
\(\log \frac{x}{m}=\log k+\frac{1}{n} \log C\)
On plotting a graph of \(\log \frac{\mathrm{X}}{\mathrm{m}}\) against \(\log \mathrm{C}\), a straight line is obtained. The slope of the straight line is \(\frac{1}{n}\).
\(\log \frac{x}{m}=\log k+\frac{1}{n} \log C\)
On plotting a graph of \(\log \frac{\mathrm{X}}{\mathrm{m}}\) against \(\log \mathrm{C}\), a straight line is obtained. The slope of the straight line is \(\frac{1}{n}\).
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