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MHT CET · Chemistry · Ionic Equilibrium

What is the value of pH of a NaOH solution that dissociates \(2 \%\) in its 0.01 M solution?

  1. A \(9.704\)
  2. B \(10.301\)
  3. C \(8.621\)
  4. D \(8.750\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(10.301\)

Step-by-step Solution

Detailed explanation

\[ [OH^-] = 0.01 \, M \times 0.02 = 2 \times 10^{-4} \, M \] \[ pOH = -\log_{10}(2 \times 10^{-4}) = 3.699 \]