MHT CET · Chemistry · Ionic Equilibrium
What is the value of pH of a NaOH solution that dissociates \(2 \%\) in its 0.01 M solution?
- A \(9.704\)
- B \(10.301\)
- C \(8.621\)
- D \(8.750\)
Answer & Solution
Correct Answer
(B) \(10.301\)
Step-by-step Solution
Detailed explanation
\[ [OH^-] = 0.01 \, M \times 0.02 = 2 \times 10^{-4} \, M \] \[ pOH = -\log_{10}(2 \times 10^{-4}) = 3.699 \]
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