MHT CET · Chemistry · Electrochemistry
What is the value of conductivity of \(0.01 \mathrm{M}\) solution of an electrolyte having molar conductivity \(141 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\) ?
- A \(5.64 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\)
- B \(1.41 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\)
- C \(4.23 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\)
- D \(7.09 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\)
Answer & Solution
Correct Answer
(B) \(1.41 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \Lambda_m & =\frac{K \times 1000}{M} \\ K & =\frac{\Lambda_m \times M}{1000}=\frac{141 \times 0.01}{1000} \\ & =1.41 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\end{aligned}\)
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