MHT CET · Chemistry · Solutions
What is the solubility of gas in water at \(25^{\circ} \mathrm{C}\) if partial pressure is 0.346 bar [Henry's law constant is \(\left.\quad 0.159 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{bar}^{-1}\right]\) ?
- A \(0.055 \mathrm{~mol} \mathrm{dm}^{-3}\)
- B \(0.028 \mathrm{~mol} \mathrm{dm}^{-3}\)
- C \(0.083 \mathrm{~mol} \mathrm{dm}^{-3}\)
- D \(0.11 \mathrm{~mol} \mathrm{dm}^{-3}\)
Answer & Solution
Correct Answer
(A) \(0.055 \mathrm{~mol} \mathrm{dm}^{-3}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \mathrm{S}=\mathrm{K}_{\mathrm{H}} \mathrm{P} & =0.159 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{bar}^{-1} \times 0.346 \mathrm{bar} \\ & =0.055 \mathrm{~mol} \mathrm{dm}^{-3}\end{aligned}\)
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