MHT CET · Chemistry · Ionic Equilibrium
What is the solubility of \(\mathrm{AgCl}_{(\mathrm{s})}\) if its solubility product is \(1.6 \times 10^{-10}\) ?
- A \(1.26 \times 10^{-5} \mathrm{M}\)
- B \(1.00 \times 10^{-9} \mathrm{M}\)
- C \(2.6 \times 10^{-5} \mathrm{M}\)
- D \(1.56 \times 10^{-9} \mathrm{M}\)
Answer & Solution
Correct Answer
(A) \(1.26 \times 10^{-5} \mathrm{M}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{AgCl}_{(\mathrm{s})} \rightleftharpoons \mathrm{Ag}_{\text {(aq) }}^{+}+\mathrm{Cl}_{\text {(aq) }}^{-} \\ & x=1, \mathrm{y}=1 \\ & \mathrm{~K}_{\text {sp }}=x^x \mathrm{y}^{\mathrm{y}} \mathrm{S}^{x+\mathrm{y}}=(1)^1(1)^1 \mathrm{~S}^{1+1}=\mathrm{S}^2 \\ & \mathrm{~S}=\sqrt{\mathrm{K}_{\mathrm{sp}}}=\sqrt{1.6 \times 10^{-10}} \\ & \quad=1.26 \times 10^{-5} \mathrm{M}\end{aligned}\)
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