MHT CET · Chemistry · Electrochemistry
What is the resistance of \(0.01 \mathrm{M} \mathrm{KCl}\) solution if its conductivity is \(200 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\) and cell constant is \(1 \mathrm{~cm}^{-1}\) ?
- A \(1 \times 10^{-3} \mathrm{ohm}\)
- B \(5 \times 10^{-3} \mathrm{ohm}\)
- C \(4 \times 10^{-3} \mathrm{ohm}\)
- D \(2 \times 10^{-3} \mathrm{ohm}\)
Answer & Solution
Correct Answer
(B) \(5 \times 10^{-3} \mathrm{ohm}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { Conductivity }=\frac{1}{\mathrm{R}} \cdot \frac{\ell}{\mathrm{A}} \\ & \frac{\ell}{\mathrm{A}}=\text { cell constant } \\ & 200=\frac{1}{\mathrm{R}} \times 1 \\ & \mathrm{R}=\frac{1}{200} \mathrm{ohm} \\ & \mathrm{R}=5 \times 10^{-3} \mathrm{ohm}\end{aligned}\)
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