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MHT CET · Chemistry · Electrochemistry

What is the resistance of \(0.01 \mathrm{M} \mathrm{KCl}\) solution if its conductivity is \(200 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\) and cell constant is \(1 \mathrm{~cm}^{-1}\) ?

  1. A \(1 \times 10^{-3} \mathrm{ohm}\)
  2. B \(5 \times 10^{-3} \mathrm{ohm}\)
  3. C \(4 \times 10^{-3} \mathrm{ohm}\)
  4. D \(2 \times 10^{-3} \mathrm{ohm}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(5 \times 10^{-3} \mathrm{ohm}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \text { Conductivity }=\frac{1}{\mathrm{R}} \cdot \frac{\ell}{\mathrm{A}} \\ & \frac{\ell}{\mathrm{A}}=\text { cell constant } \\ & 200=\frac{1}{\mathrm{R}} \times 1 \\ & \mathrm{R}=\frac{1}{200} \mathrm{ohm} \\ & \mathrm{R}=5 \times 10^{-3} \mathrm{ohm}\end{aligned}\)