MHT CET · Chemistry · Solutions
What is the relation between the vapour pressure of solution, vapour pressure of solvent and its mole fraction in the solution?
- A \(\mathrm{P}_1=\mathrm{P}_1^{*} x_1\)
- B \(\mathrm{P}_1^{*}=\mathrm{P}_1 x_1\)
- C \(\mathrm{P}_1=\mathrm{P}_1^* x_2\)
- D \(\mathrm{P}_1^{*}=\mathrm{P}_1 x_2\)
Answer & Solution
Correct Answer
(A) \(\mathrm{P}_1=\mathrm{P}_1^{*} x_1\)
Step-by-step Solution
Detailed explanation
The relation between the vapour pressure of the solution \(\left(P_1\right)\), the vapour pressure of the pure solvent \(\left(P_1^*\right)\), and the mole fraction of the solvent \(\left(x_1\right)\) in the solution is given by Raoult's Law for an ideal solution.
Raoult's Law states:
\(P_1=P_1^* \cdot x_1\)
Where:
- \(P_1\) is the vapour pressure of the solvent in the solution,
- \(P_1^*\) is the vapour pressure of the pure solvent,
- \(x_1\) is the mole fraction of the solvent in the solution.
The correct relation is (1):
\(P_1=P_1^* \cdot x_1\)
Raoult's Law states:
\(P_1=P_1^* \cdot x_1\)
Where:
- \(P_1\) is the vapour pressure of the solvent in the solution,
- \(P_1^*\) is the vapour pressure of the pure solvent,
- \(x_1\) is the mole fraction of the solvent in the solution.
The correct relation is (1):
\(P_1=P_1^* \cdot x_1\)
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