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MHT CET · Chemistry · Solutions

What is the relation between the depression in freezing point and molar mass of non-volatile solute?

  1. A \(\mathrm{M}_2=\frac{1000 \mathrm{~K}_{\mathrm{f}} \mathrm{W}_1}{\Delta \mathrm{T}_{\mathrm{f}} \mathrm{W}_2}\)
  2. B \(\mathrm{M}_2=\frac{\Delta \mathrm{T}_{\mathrm{f}} \mathrm{W}_1}{1000 \mathrm{~K}_{\mathrm{f}} \mathrm{W}_2}\)
  3. C \(\mathrm{M}_2=\frac{1000 \Delta \mathrm{T}_{\mathrm{f}} \mathrm{W}_2}{\mathrm{~K}_{\mathrm{f}} \mathrm{W}_1}\)
  4. D \(\mathrm{M}_2=\frac{1000 \mathrm{~K}_{\mathrm{f}} \mathrm{W}_2}{\Delta \mathrm{T}_{\mathrm{f}} \mathrm{W}_1}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\mathrm{M}_2=\frac{1000 \mathrm{~K}_{\mathrm{f}} \mathrm{W}_2}{\Delta \mathrm{T}_{\mathrm{f}} \mathrm{W}_1}\)

Step-by-step Solution

Detailed explanation

\(\Delta_{\mathrm{f}}^{\mathrm{T}}=\mathrm{K}_{\mathrm{f}} \cdot \frac{\mathrm{W}_2}{\mathrm{M}_2} \times \frac{1000}{\mathrm{~W}_1}\)