MHT CET · Chemistry · Chemical Kinetics
What is the rate of appearance of \(\mathrm{Z}\) in following reaction?
\(3 \mathrm{x} \rightarrow 2 \mathrm{y}+\mathrm{z}\), if rate of disappearance of \(\mathrm{x}\) is \(0.072 \mathrm{~mol} \mathrm{~s}^{-1}\)
- A \(0.072 \mathrm{~mol} \mathrm{~s}^{-1}\)
- B \(0.048 \mathrm{~mol} \mathrm{~s}^{-1}\)
- C \(0.024 \mathrm{~mol} \mathrm{~s}^{-1}\)
- D \(0.096 \mathrm{~mol} \mathrm{~s}^{-1}\)
Answer & Solution
Correct Answer
(C) \(0.024 \mathrm{~mol} \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
\(
3 \mathrm{x} \longrightarrow 2 \mathrm{y}+\mathrm{Z}
\)
\(\frac{\text { Rate of disappearance of } x}{3}=\frac{\text { Rate of appearance of } \mathrm{Z}}{1}\)
Rate of appearance of \(\mathrm{Z}=\frac{1}{3} \times 0.072\) \(=0.024 \mathrm{~mol} \mathrm{~s}^{-1}\).
3 \mathrm{x} \longrightarrow 2 \mathrm{y}+\mathrm{Z}
\)
\(\frac{\text { Rate of disappearance of } x}{3}=\frac{\text { Rate of appearance of } \mathrm{Z}}{1}\)
Rate of appearance of \(\mathrm{Z}=\frac{1}{3} \times 0.072\) \(=0.024 \mathrm{~mol} \mathrm{~s}^{-1}\).
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