MHT CET · Chemistry · Classification of Elements and Periodicity in Properties
What is the position of elements \(\mathrm{La}(\mathrm{Z}=57)\) and \(\mathrm{Ce}(\mathrm{Z}=58)\) respectively in the long form of periodic table?
- A \(\mathrm{La}=\) Group-3, Period-6 \(\mathrm{Ce}=\) Group-3, Period-6
- B La \(=\) Group \(-4\), Period-7 \(\mathrm{Ce}=\) Group-5, Period-7
- C \(\mathrm{La}=\) Group \(-3\), Period-7 \(\mathrm{Ce}=\) Group-3, Period-6
- D \(\mathrm{La}=\) Group-3, Period-6 \(\mathrm{Ce}=\) Group-3, Period-7
Answer & Solution
Correct Answer
(A) \(\mathrm{La}=\) Group-3, Period-6 \(\mathrm{Ce}=\) Group-3, Period-6
Step-by-step Solution
Detailed explanation
\(\mathrm{Zn}^{2+} \longrightarrow 3 \mathrm{~d}^{10}\) (No unpaired d-electron)
\(\therefore \mathrm{Zn}\) forms colourless compounds in \(+2\) oxidation state.
\(\therefore \mathrm{Zn}\) forms colourless compounds in \(+2\) oxidation state.
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