MHT CET · Chemistry · Ionic Equilibrium
What is the pH of buffer solution prepared by mixing 0.01 M weak acid and 0.02 M salt of weak acid with strong base ?
\(\left(\mathrm{pK}_{\mathrm{a}}=4 \cdot 680\right)\)
- A \(4 \cdot 379\)
- B \(2 \cdot 379\)
- C \(4.981\)
- D \(2 \cdot 981\)
Answer & Solution
Correct Answer
(C) \(4.981\)
Step-by-step Solution
Detailed explanation
\(\mathrm{pH} = \mathrm{pK}_{\mathrm{a}} + \log \left( \frac{[\text{salt}]}{[\text{acid}]} \right)\) \(\mathrm{pH} = 4.680 + \log \left( \frac{0.02}{0.01} \right)\)
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