MHT CET · Chemistry · Ionic Equilibrium
What is the \(\mathrm{pH}\) of \(0.005 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4\) solution?
- A 5
- B 2.3
- C 3.3
- D 2
Answer & Solution
Correct Answer
(D) 2
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{H}_2 \mathrm{SO}_4 \longrightarrow 2 \mathrm{H}^{+}+\mathrm{SO}_4^{2-} \\ & {\left[\mathrm{H}_2 \mathrm{SO}_4\right]=0.005 \mathrm{M}} \\ & {\left[\mathrm{H}^{+}\right]=2 \times 0.005=0.01 \mathrm{M}} \\ & \mathrm{pH}=-\log \left[\mathrm{H}^{+}\right]=-\log 0.01 \\ & \mathrm{pH}=2\end{aligned}\)
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