MHT CET · Chemistry · Solutions
What is the percentage dissociation of \(0.1 \mathrm{M}\) acetic acid?
\(\left(\mathrm{Ka}=10^{-5}\right)\)
- A \(1 \%\)
- B \(10 \%\)
- C \(0.1 \%\)
- D \(0.01 \%\)
Answer & Solution
Correct Answer
(A) \(1 \%\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{K}_{\mathrm{a}}=\propto^2 \mathrm{C} \\ & 10^{-5}=\propto^2 \times 0.1 \\ & \propto=0.01 \text { or } 1 \%\end{aligned}\)
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