MHT CET · Chemistry · Redox Reactions
What is the oxidation number of Cr in \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) ?
- A \(+2\)
- B \(+12\)
- C \(-6\)
- D \(+6\)
Answer & Solution
Correct Answer
(D) \(+6\)
Step-by-step Solution
Detailed explanation
\(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} =(1 \times 2)+(\mathrm{x} \times 2)+[(-2) \times 7] \)
\( =2+2 \mathrm{x}-14 \)
\( =2 \mathrm{x}-12 \)
\( \therefore 2 \mathrm{x} =12 \)
\( \therefore \mathrm{x} =+6\)
\(\therefore\) Oxidation number of \(\mathrm{Cr}=+6\)
\( =2+2 \mathrm{x}-14 \)
\( =2 \mathrm{x}-12 \)
\( \therefore 2 \mathrm{x} =12 \)
\( \therefore \mathrm{x} =+6\)
\(\therefore\) Oxidation number of \(\mathrm{Cr}=+6\)
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