MHT CET · Chemistry · Redox Reactions
What is the oxidation number of Carbon in \(\mathrm{K}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\)?
- A \(+3\)
- B \(-2\)
- C 0
- D \(+4\)
Answer & Solution
Correct Answer
(A) \(+3\)
Step-by-step Solution
Detailed explanation
\(\mathrm{K}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \Rightarrow(1 \times 2)+(\mathrm{x} \times 2)+(-2 \times 4)\)
\(=2+2 x-8\)
\(=2 x-6\)
\(\therefore x=+3\)
\(\therefore\) The oxidation number of \(C=+3\)
\(=2+2 x-8\)
\(=2 x-6\)
\(\therefore x=+3\)
\(\therefore\) The oxidation number of \(C=+3\)
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