MHT CET · Chemistry · Solutions

What is the osmotic pressure of solution prepared by dissolving 3 gram solute in \(2 \mathrm{dm}^3\) water at 300 K .
(Molar mass of solute \(=60 \mathrm{~g} \mathrm{~mol}{ }^{-1}\), \(\mathrm{R}=0.0821 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~K}{ }^{-1} \mathrm{~mol}^{-1}\) )

A 0.76 atc m
B 0.62 atm
C 0.51 atm
D 0.84 atm

Verified Solution

Answer & Solution

Correct Answer

(B) 0.62 atm

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \pi=\mathrm{MRT} \\ & \pi=\frac{\mathrm{n}_2 \mathrm{RT}}{\mathrm{V}}=\frac{\frac{3}{60} \times 0.082 \times 300}{2}=0.62 \mathrm{~atm}\end{aligned}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From MHT CET

Explore more questions on app

What is the osmotic pressure of solution prepared by dissolving 3 gram solute in \(2 \mathrm{dm}^3\) water at 300 K .(Molar mass of solute \(=60 \mathrm{~g} \mathrm{~mol}{ }^{-1}\), \(\mathrm{R}=0.0821 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~K}{ }^{-1} \mathrm{~mol}^{-1}\) )

Step-by-step Solution

What is the osmotic pressure of solution prepared by dissolving 3 gram solute in \(2 \mathrm{dm}^3\) water at 300 K .
(Molar mass of solute \(=60 \mathrm{~g} \mathrm{~mol}{ }^{-1}\), \(\mathrm{R}=0.0821 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~K}{ }^{-1} \mathrm{~mol}^{-1}\) )