MHT CET · Chemistry · d and f Block Elements
What is the numerical value of spin only magnetic moment of copper in +2 state?
- A 0
- B 1.73
- C 2.78
- D 4.4
Answer & Solution
Correct Answer
(B) 1.73
Step-by-step Solution
Detailed explanation
\(\mathrm{Cu}(\mathrm{Z}=29):[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^1 \)
\( \mathrm{Cu}^{2+}:[\mathrm{Ar}] 3 \mathrm{~d}^9 \)
\( \text { No. of unpaired } \mathrm{e}^{-}=1 \)
\( \mu=\sqrt{\mathrm{n}(\mathrm{n}+2)}=\sqrt{1(1+2)}=\)\(\sqrt{3}=1.73 \mathrm{BM}\)
\( \mathrm{Cu}^{2+}:[\mathrm{Ar}] 3 \mathrm{~d}^9 \)
\( \text { No. of unpaired } \mathrm{e}^{-}=1 \)
\( \mu=\sqrt{\mathrm{n}(\mathrm{n}+2)}=\sqrt{1(1+2)}=\)\(\sqrt{3}=1.73 \mathrm{BM}\)
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