MHT CET · Chemistry · Some Basic Concepts of Chemistry
What is the number of hydrogen atoms present in 5.4 g of urea?
- A \(9.011 \times 10^{23}\)
- B \(6.022 \times 10^{23}\)
- C \(2.168 \times 10^{23}\)
- D \(3.011 \times 10^{23}\)
Answer & Solution
Correct Answer
(C) \(2.168 \times 10^{23}\)
Step-by-step Solution
Detailed explanation
\(\text{Molar mass of urea} (\text{CO(NH}_2)_2) = 12 + 16 + 2(14 + 2 \times 1) = 60 \text{ g/mol}\) \(\text{Number of H atoms} = \frac{5.4 \text{ g}}{60 \text{ g/mol}} \times 6.022 \times 10^{23} \text{ molecules/mol} \times 4 = 2.168 \times 10^{23}\)
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