MHT CET · Chemistry · Electrochemistry
What is the number of electrons passed through an electrolyte solution when 1 ampere current is passed for 16.1 minutes?
- A \(5.022 \times 10^{24}\)
- B \(3.011 \times 10^{22}\)
- C \(6.022 \times 10^{21}\)
- D \(2.022 \times 10^{23}\)
Answer & Solution
Correct Answer
(C) \(6.022 \times 10^{21}\)
Step-by-step Solution
Detailed explanation
\(
\begin{aligned}
& \mathrm{q}=\mathrm{ne} \\
& \mathrm{q}=\mathrm{I} . \mathrm{t} \\
& \mathrm{n}=\text { no. of electrons } \\
& \mathrm{e}=\text { change of one electron } \\
& \mathrm{I}=\text { Current supplied } \\
& \mathrm{t}=\text { time in seconds } \\
& \mathrm{q}=1 \times 16.1 \times 60=\mathrm{ne} \\
& \mathrm{n}=\frac{16.1 \times 60}{1.602 \times 10^{-19}}=6.022 \times 10^{21}
\end{aligned}
\)
\begin{aligned}
& \mathrm{q}=\mathrm{ne} \\
& \mathrm{q}=\mathrm{I} . \mathrm{t} \\
& \mathrm{n}=\text { no. of electrons } \\
& \mathrm{e}=\text { change of one electron } \\
& \mathrm{I}=\text { Current supplied } \\
& \mathrm{t}=\text { time in seconds } \\
& \mathrm{q}=1 \times 16.1 \times 60=\mathrm{ne} \\
& \mathrm{n}=\frac{16.1 \times 60}{1.602 \times 10^{-19}}=6.022 \times 10^{21}
\end{aligned}
\)
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