MHT CET · Chemistry · Coordination Compounds
What is the number of electrons lost by Cr in a complex \(\left[\mathrm{Cr}(\mathrm{CO})_6\right]\) ?
- A 0
- B 4
- C 6
- D 2
Answer & Solution
Correct Answer
(A) 0
Step-by-step Solution
Detailed explanation
Since carbonyl (CO) is a neutral ligand, oxidation state of Cr in \(\left[\mathrm{Cr}(\mathrm{CO})_6\right]\) is 0 . Hence, no electron will be lost by Cr . in the complex.
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