MHT CET · Chemistry · Solutions
What is the molar mass of solute when 5 gram solute dissolved in 70 gran solvent lowers its freezing point by \(2.5 \mathrm{~K}\) ? If \(\mathrm{K}_{\mathrm{f}}=3.5 \mathrm{~K}-\mathrm{Kg} / \mathrm{mol}\).
- A \(100 \mathrm{~g} \mathrm{~mol}^{-1}\)
- B \(120 \mathrm{~g} \mathrm{~mol}^{-1}\)
- C \(160 \mathrm{~g} \mathrm{~mol}^{-1}\)
- D \(140 \mathrm{~g} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(A) \(100 \mathrm{~g} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\Delta \mathrm{T}_{\mathrm{f}}=\mathrm{K}_{\mathrm{f}} \times \mathrm{m}\)
\(2.5=3.5 \times \frac{5}{M} \times \frac{1000}{70}\)
\(\mathrm{M}=100 \mathrm{~g} / \mathrm{mol}\)
\(2.5=3.5 \times \frac{5}{M} \times \frac{1000}{70}\)
\(\mathrm{M}=100 \mathrm{~g} / \mathrm{mol}\)
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