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MHT CET · Chemistry · Haloalkanes and Haloarenes

What is the molar mass of product hydrocarbon when 2 moles of methyl bromide reacts with large excess of sodium in dry ether?

  1. A \(15.0 \mathrm{~g} \mathrm{~mol}^{-1}\)
  2. B \(30.0 \mathrm{~g} \mathrm{~mol}^{-1}\)
  3. C \(7.5 \mathrm{~g} \mathrm{~mol}^{-1}\)
  4. D \(40.0 \mathrm{~g} \mathrm{~mol}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(30.0 \mathrm{~g} \mathrm{~mol}^{-1}\)

Step-by-step Solution

Detailed explanation


Thus, the molar mass of the product formed, i.e., ethane is \(30.0 \mathrm{~g} \mathrm{~mol}^{-1}\).