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MHT CET · Chemistry · Electrochemistry

What is the molar conductivity of \(0.005 \mathrm{M}\) \(\mathrm{NaI}\) solution if its conductivity is \(6.065 \times 10^{-4} \Omega^{-1} \mathrm{~cm}^{-1}\) ?

  1. A \(121.3 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
  2. B \(115.1 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
  3. C \(126.5 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
  4. D \(131.2 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(121.3 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)

Step-by-step Solution

Detailed explanation

\(\wedge_{\mathrm{m}}=\frac{1000 \mathrm{k}}{\mathrm{c}}\)
\(=\frac{1000 \times 6.065 \times 10^{-4}}{0.005}=121.3 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\)