MHT CET · Chemistry · Solid State
What is the mass of bcc type unit cell of sodium if mass of one atom of sodium is \(3 \cdot 819 \times 10^{-23} \mathrm{~g}\) ?
- A \(7 \cdot 038 \times 10^{-23} \mathrm{~g}\)
- B \(7 \cdot 638 \times 10^{-23} \mathrm{~g}\)
- C \(3 \cdot 819 \times 10^{-23} \mathrm{~g}\)
- D \(1.5276 \times 10^{-22} \mathrm{~g}\)
Answer & Solution
Correct Answer
(B) \(7 \cdot 638 \times 10^{-23} \mathrm{~g}\)
Step-by-step Solution
Detailed explanation
No. of atoms per bcc type of unit cell, \(\mathrm{n}=2\)
Mass of bcc unit cell \(=\) Mass of two atoms
\(\therefore \text {Mass of bcc unit cell of } \mathrm{Na}\) \(=3.819 \times 10^{-23} \times 2\)
\(=7.638 \times 10^{-23} \mathrm{~g}\)
Mass of bcc unit cell \(=\) Mass of two atoms
\(\therefore \text {Mass of bcc unit cell of } \mathrm{Na}\) \(=3.819 \times 10^{-23} \times 2\)
\(=7.638 \times 10^{-23} \mathrm{~g}\)
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