MHT CET · Chemistry · Solid State
What is the mass of an fcc unit cell if mass of one atom of an element is \(6 \times 10^{-23} \mathrm{~g}\) ?
- A \(24 \times 10^{-22} \mathrm{~g}\)
- B \(4 \times 10^{-23} \mathrm{~g}\)
- C \(2 \cdot 4 \times 10^{-22} \mathrm{~g}\)
- D \(2 \cdot 4 \times 10^{-23} \mathrm{~g}\)
Answer & Solution
Correct Answer
(C) \(2 \cdot 4 \times 10^{-22} \mathrm{~g}\)
Step-by-step Solution
Detailed explanation
In FCC, No. of atoms per unit cell \(=4\)
Mass of unit cell \(=\) Mass of 4 atoms \(=4 \times 6 \times 10^{-23} \mathrm{~g}\)
\(=24 \times 10^{-23} \mathrm{~g}=2.4 \times 10^{-22} \mathrm{~g}\)
Mass of unit cell \(=\) Mass of 4 atoms \(=4 \times 6 \times 10^{-23} \mathrm{~g}\)
\(=24 \times 10^{-23} \mathrm{~g}=2.4 \times 10^{-22} \mathrm{~g}\)
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