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MHT CET · Chemistry · Solid State

What is the mass of an fcc unit cell if mass of one atom of an element is \(6 \times 10^{-23} \mathrm{~g}\) ?

  1. A \(24 \times 10^{-22} \mathrm{~g}\)
  2. B \(4 \times 10^{-23} \mathrm{~g}\)
  3. C \(2 \cdot 4 \times 10^{-22} \mathrm{~g}\)
  4. D \(2 \cdot 4 \times 10^{-23} \mathrm{~g}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2 \cdot 4 \times 10^{-22} \mathrm{~g}\)

Step-by-step Solution

Detailed explanation

In FCC, No. of atoms per unit cell \(=4\)
Mass of unit cell \(=\) Mass of 4 atoms \(=4 \times 6 \times 10^{-23} \mathrm{~g}\)
\(=24 \times 10^{-23} \mathrm{~g}=2.4 \times 10^{-22} \mathrm{~g}\)