MHT CET · Chemistry · Some Basic Concepts of Chemistry
What is the mass of \(33.6 \mathrm{dm}^3\) of methane gas at S.T.P.?
- A \(4.8 \times 10^{-2} \mathrm{~kg}\)
- B \(3.3 \times 10^{-2} \mathrm{~kg}\)
- C \(1.6 \times 10^{-2} \mathrm{~kg}\)
- D \(2.4 \times 10^{-2} \mathrm{~kg}\)
Answer & Solution
Correct Answer
(D) \(2.4 \times 10^{-2} \mathrm{~kg}\)
Step-by-step Solution
Detailed explanation
\(\text {moles of gas }=\frac{\text { volume }}{22.4}=\frac{33.6}{22.4}=1.5 \)
\( \text {mass of } \left(\mathrm{CH}_4\right) \text { methane gas } =\text { moles }\)\(\times \text { molar mass } \)
\( =1.5 \times 16 \)
\( =24 \mathrm{~g} \)
\( =2.4 \times 10^{-2} \mathrm{~kg}\)
\( \text {mass of } \left(\mathrm{CH}_4\right) \text { methane gas } =\text { moles }\)\(\times \text { molar mass } \)
\( =1.5 \times 16 \)
\( =24 \mathrm{~g} \)
\( =2.4 \times 10^{-2} \mathrm{~kg}\)
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