MHT CET · Chemistry · Solutions
What is the freezing point of 1 molal aqueous solution of a non-volatile solute?
\(
\left(\mathrm{K}_{\mathrm{f}}=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right)\left(\mathrm{T}_{\mathrm{f}}^{\circ} \text { for water }=0^{\circ} \mathrm{C}\right)
\)
- A \(-0.93^{\circ} \mathrm{C}\)
- B \(-2.43^{\circ} \mathrm{C}\)
- C \(-3.72^{\circ} \mathrm{C}\)
- D \(-1.86^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(D) \(-1.86^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \Delta \mathrm{T}_{\mathrm{f}}=\mathrm{T}_{\mathrm{f}}^{\circ}-\mathrm{T}_{\mathrm{f}}=\mathrm{k}_{\mathrm{f}} \cdot \mathrm{m} \\ & 0^{\circ} \mathrm{C}-\mathrm{T}_{\mathrm{f}}=1.86 \times 1 \\ & \mathrm{~T}_{\mathrm{f}}=-1.86^{\circ} \mathrm{C}\end{aligned}\)
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