MHT CET · Chemistry · Chemical Bonding and Molecular Structure
What is the formal charge of oxygen atoms in carbon monoxide?
- A 2
- B 1
- C -1
- D Zero
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
Lewis's structure of carbon monoxide \(\Rightarrow: \mathrm{C} \equiv \mathrm{O}\) :
Formal charge \(=\left[\begin{array}{c}\text { Total no.of valence } \\ e^{-} \text {infreestate }\end{array}\right]\) \(-\left[\begin{array}{c}\text { Total no.of lone } \\ \text { pairelectrons }\end{array}\right]\) \(-\frac{1}{2}\left[\begin{array}{c}\text { no. of bonding electrons } \\ \text { on thatparticularatom }\end{array}\right]\)
\(=6-2-\frac{1}{2} \times 6\)
\(=+1\)
Formal charge \(=\left[\begin{array}{c}\text { Total no.of valence } \\ e^{-} \text {infreestate }\end{array}\right]\) \(-\left[\begin{array}{c}\text { Total no.of lone } \\ \text { pairelectrons }\end{array}\right]\) \(-\frac{1}{2}\left[\begin{array}{c}\text { no. of bonding electrons } \\ \text { on thatparticularatom }\end{array}\right]\)
\(=6-2-\frac{1}{2} \times 6\)
\(=+1\)
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