MHT CET · Chemistry · Ionic Equilibrium
What is the expression for solubility product of silver chromate if it's solubility is expressed as \(\mathrm{S}\) mol L\({ }^{-1}\) ?
- A \(2 \mathrm{~S}^2\)
- B \(3 \mathrm{~S}^3\)
- C \(4 \mathrm{~S}^3\)
- D \(27 \mathrm{~S}^4\)
Answer & Solution
Correct Answer
(C) \(4 \mathrm{~S}^3\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{ll} & \mathrm{Ag}_2 \mathrm{CrO}_{4(\mathrm{~s})} \rightleftharpoons 2 \mathrm{Ag}_{(\mathrm{aq})}^{+}+\mathrm{CrO}_{4(\mathrm{aq})}^{2-} \\ & \mathrm{Here}, x=2, \mathrm{y}=1 \\ \therefore \quad & \mathrm{K}_{\mathrm{sp}}=x^x \mathrm{y}^{\mathrm{y}} \mathrm{S}^{x+\mathrm{y}}=(2)^2(1)^1 \mathrm{~S}^{2+1}=4 \mathrm{~S}^3\end{array}\)
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