MHT CET · Chemistry · Thermodynamics (C)
What is the constant external pressure of an ideal gas when expanded from \(2 \times 10^{-2} \mathrm{~m}^3\) to \(3 \times 10^{-2} \mathrm{~m}^3\), if the work done by the gas is \(-5.09 \mathrm{~kJ}\) ?
- A \(5.09 \times 10^5 \mathrm{Nm}^{-2}\)
- B \(1.01 \times 10^5 \mathrm{Nm}^{-2}\)
- C \(2.02 \times 10^5 \mathrm{Nm}^{-2}\)
- D \(5.60 \times 10^5 \mathrm{Nm}^{-2}\)
Answer & Solution
Correct Answer
(A) \(5.09 \times 10^5 \mathrm{Nm}^{-2}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{W}=-\mathrm{P}_{\text {ext }}\left[\mathrm{V}_2-\mathrm{V}_1\right] \\ & \mathrm{W}=-5.09 \mathrm{~kJ} \\ & =-5090 \mathrm{~J} \\ & -5090=-\mathrm{P}_{\text {ext }}\left[3 \times 10^{-2}-2 \times 10^{-2}\right] \\ & 5090=\operatorname{Pext} \times 1 \times 10^{-2} \\ & \mathrm{P}_{\text {ext }}=509000 \mathrm{Nm}^{-2} \\ & =5.09 \times 10^5 \mathrm{Nm}^{-2}\end{aligned}\)
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