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MHT CET · Chemistry · Electrochemistry

What is the conductivity of 0.05 M NaOH solution having resistance 31.5 ohm and cell constant \(0.315 \mathrm{~cm}^{-1}\) ?

  1. A \(100 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
  2. B \(0.02 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
  3. C \(0.09 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
  4. D \(0.01 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(0.01 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & k=\frac{1}{R} \times \frac{l}{A} \\ & =\frac{1}{31.5 \mathrm{ohm}} \times 0.315 \mathrm{~cm}^{-1} \\ \therefore \quad k & =0.01 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\end{aligned}\)