MHT CET · Chemistry · Electrochemistry
What is the conductivity of 0.05 M NaOH solution having resistance 31.5 ohm and cell constant \(0.315 \mathrm{~cm}^{-1}\) ?
- A \(100 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
- B \(0.02 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
- C \(0.09 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
- D \(0.01 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
Answer & Solution
Correct Answer
(D) \(0.01 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & k=\frac{1}{R} \times \frac{l}{A} \\ & =\frac{1}{31.5 \mathrm{ohm}} \times 0.315 \mathrm{~cm}^{-1} \\ \therefore \quad k & =0.01 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\end{aligned}\)
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