MHT CET · Chemistry · Electrochemistry
What is the conductivity of 0.02 M AgNO 3 solution having cell constant \(1.1 \mathrm{~cm}^{-1}\) and resistance is 94.5 ohms?
- A \(0.0216 . \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
- B \(0.0116 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
- C \(0.0416 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
- D \(0.0859 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
Answer & Solution
Correct Answer
(B) \(0.0116 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\text {Conductivity }(\mathrm{k}) =\frac{\text { Cell constant }}{\mathrm{R}} \)
\( =\frac{1.1 \mathrm{~cm}^{-1}}{94.5 \mathrm{ohms}} \)
\( =0.0116 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
\( =\frac{1.1 \mathrm{~cm}^{-1}}{94.5 \mathrm{ohms}} \)
\( =0.0116 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\)
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