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MHT CET · Chemistry · Electrochemistry

What is the concentration of an electrolyte solution to have molar conductivity of \(101 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\) and conductivity of \(1.01 \times 10^{-2} \Omega^{-1} \mathrm{~cm}^{-1}\) at 298 K ?

  1. A 0.05 M
  2. B 0.1 M
  3. C 0.15 M
  4. D 0.2 M
Verified Solution

Answer & Solution

Correct Answer

(B) 0.1 M

Step-by-step Solution

Detailed explanation

\(\text {Molar conductivity }(\wedge)=\frac{1000 \mathrm{k}}{\mathrm{c}} \)
\( 101 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}=\frac{1000 \times 1.01 \Omega^{-1} \mathrm{~cm}^{-1} \times 10^{-2}}{\mathrm{c}} \)
\( \therefore \mathrm{c}=\frac{1000 \times 1.01 \times 10^{-2}}{101}=0.1 \mathrm{M}\)