MHT CET · Chemistry · Electrochemistry
What is the change in potential of following cell \(\mathrm{Zn}(\mathrm{s})\left|\begin{array}{c}\mathrm{Zn} \mathrm{n}^{2+} \ 1 \mathrm{M}\end{array}\right| \begin{gathered}\mathrm{Pb}^{2+} \ 1 \mathrm{M}\end{gathered} \mid \mathrm{Pb}(\mathrm{s})\) if concentration of ions at anode is increased 10 times?
- A Decreases by 0.0296 volt
- B Increases by 10 volt
- C Decreases by 10 volt
- D Increase by 0.0296 volt
Answer & Solution
Correct Answer
(A) Decreases by 0.0296 volt
Step-by-step Solution
Detailed explanation
\(\mathrm{E}_{\text {cell }}=\mathrm{E}_{\text {cell }}^0-\frac{0.0591}{2} \log \frac{\left[\mathrm{Zn}^{+2}\right]}{\left[\mathrm{Pb}^{+2}\right]}\)
As conc. of \(\mathrm{Zn}^{+2}\) increases 10 times, \(\mathrm{E}_{\text {cell }}\) decreases by 0.0296 volts.
As conc. of \(\mathrm{Zn}^{+2}\) increases 10 times, \(\mathrm{E}_{\text {cell }}\) decreases by 0.0296 volts.
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