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MHT CET · Chemistry · Electrochemistry

What is the cell constant, if two platinum electrodes in conductivity cell are separated by 0.92 cm and area of cross section is \(1.2 \mathrm{~cm}^2\) ?

  1. A \(0.767 \mathrm{~cm}^{-1}\)
  2. B \(0.906 \mathrm{~cm}^{-1}\)
  3. C \(1.304 \mathrm{~cm}^{-1}\)
  4. D \(1.104 \mathrm{~cm}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0.767 \mathrm{~cm}^{-1}\)

Step-by-step Solution

Detailed explanation

Cell constant \(=\frac{l}{\mathrm{a}}=\frac{0.92 \mathrm{~cm}}{1.2 \mathrm{~cm}^2}=0.767 \mathrm{~cm}^{-1}\)