MHT CET · Chemistry · Chemical Bonding and Molecular Structure
What is the bond order of \(\mathrm{Be}_{2}\) molecule?
- A 2
- B 3
- C 0
- D 1
Answer & Solution
Correct Answer
(C) 0
Step-by-step Solution
Detailed explanation
In \(\mathrm{Be}_{2}\) molecule,
\(\sigma_{1s^{2}} \sigma_{1s^{2}}^{*} \sigma_{2 s^{2}} \sigma_{2 s^{2}}^{*}\)
\(N_{b}=4 \quad N_{a}=4\)
Bond order \(=\frac{N_{b}-N_{a}}{2}=0\)
\(\sigma_{1s^{2}} \sigma_{1s^{2}}^{*} \sigma_{2 s^{2}} \sigma_{2 s^{2}}^{*}\)
\(N_{b}=4 \quad N_{a}=4\)
Bond order \(=\frac{N_{b}-N_{a}}{2}=0\)
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