MHT CET · Chemistry · Chemical Bonding and Molecular Structure
What is the bond order of \(\mathrm{B}_{2}\) molecule?
- A 0
- B 1
- C 3
- D 2
Answer & Solution
Correct Answer
(A) 0
Step-by-step Solution
Detailed explanation
(C)
Bond order \(=\frac{\mathrm{N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}}{2}=\frac{4-2}{2}=1\)

Bond order \(=\frac{\mathrm{N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}}{2}=\frac{4-2}{2}=1\)

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