MHT CET · Chemistry · Chemical Bonding and Molecular Structure
What is the bond order in \(\mathrm{N}_{2}\) Molecule?
- A 2
- B zero
- C 1
- D 3
Answer & Solution
Correct Answer
(D) 3
Step-by-step Solution
Detailed explanation
(C)
\(\therefore\) Bond order \(=\frac{\mathrm{N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}}{2}=\frac{8-2}{2}=3\)
\(\therefore\) Bond order \(=\frac{\mathrm{N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}}{2}=\frac{8-2}{2}=3\)
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